Doug Sears
"Marc R" wrote:
> if the road rises 5 ft for every 100 foot HORIZONTAL change (so grade =
> 5% and slope = 5/100 or .05). But in looking at some Tour de France
> numbers last summer I concluded that that was NOT how the grade of a
> climb there is measured. Can anyone explain their system? Is their
> 'grade' maybe the ratio of the vertical change to the actual change in
> distance of the rider -- i.e., the ratio of the vertical leg of the
> appropropriate right triangle to the HYPOTENUSE? Help! ;)
Using Marc's example of a 5% grade, the hypotenuse (distance traveled by
the cyclist) would be 100.12 feet for every 100 foot horizontal distance.
To look at it another way, if you mistakenly calculate the grade by
dividing the vertical change by the distance traveled, you'd get a grade of
4.99% instead of 5% -- hardly worth worrying about. This is because the
angle involved (2.86 degrees) is small. The sine of A is approximately
equal to A when A is small.
--Doug Sears